# Line slope calculator 2x-4y=-26

**Straight line given by points A[3; 8] and B[7; 10]**

## Calculation:

**Slope-intercept form of line:**y = 0.5x+6.5

**Canonical form of the line equation:**2x-4y+26 = 0

**Parametric form of the line equation:**

x = 4t+3

y = 2t+8 ; t ∈ R

**Slope:**m = 0.5

**Slope angle of line: φ =**26°33'54″ = 0.4636 rad

**X intercept:**x

_{0}= -13

**Y intercept:**y

_{0}= q = 6.5

**Distance line from the origin:**d

_{0}= 5.8138

**The length of the segment AB: |AB| =**4.4721

**Vector: AB =**(4; 2)

**Normal vector: n =**(2; -4)

**Midpoint of the segment AB: M =**[5; 9]

**Perpendicular Bisector equation:**4x+2y-38 = 0

**Vector OA = (3; 8) ; |OA| = 8.544**

**Vector OB = (7; 10) ; |OB| = 12.2066**

**Scalar product OA .OB = 101**

**Angle ∠ AOB = 14°26'9″ = 0.252 rad**